(x^2D^2+xD+1)y=logx

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Solution for (x^2D^2+xD+1)y=logx equation: 


Simplifying
(x2D2 + xD + 1) * y = logx

Reorder the terms:
(1 + xD + x2D2) * y = logx

Reorder the terms for easier multiplication:
y(1 + xD + x2D2) = logx
(1 * y + xD * y + x2D2 * y) = logx

Reorder the terms:
(xyD + x2yD2 + 1y) = logx
(xyD + x2yD2 + 1y) = logx

Solving
xyD + x2yD2 + 1y = glox

Solving for variable 'x'.

Reorder the terms:
-1glox + xyD + x2yD2 + 1y = glox + -1glox

Combine like terms: glox + -1glox = 0
-1glox + xyD + x2yD2 + 1y = 0

The solution to this equation could not be determined.

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